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100% Waec 2018 Real (Physics Practical) Answers Available Here..
Author: Mr. Dan
Posted on: 09:55:12 Tue, 03 Apr 2018


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Click here for NO 1 SOLUTION IN IMAGE FORM and GRAPH
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Click here for NO 1 SOLUTION IN IMAGE FORM and GRAPH




(1a)
TABULATE:
S/N: 1, 2 , 3, 4, 5
L(cm): 90.00, 80.00, 70.00, 60.00, 50.00
T(s): 38.00, 36.00, 34.00, 31.00, 28.00
T = t/20(sqt): 1.90, 1.80, 1.70, 1.55, 1.40
√L(cm^1/2): 9.49, 8.94, 8.37, 7.73, 7.07

(1aix)
Slope(s) = Δvertical/Δhorizontal
=1.90 - 1.55/9.49 - 7.75
= 0.35/1.74
S = 0.201

(1ax)
g = 4π²/S²
= 4 ×(3.142)²/(0.201)²
= 977.4cm/s²

(1axi)
(i) I ensured the angle of oscillation is relatively small.
(ii) I ensured that no external force is added to the system of oscillation.
(iii) I ensured the oscillation is perfect

(1b)
Click here to view the Diagram

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Click here for NO 3 GRAPH
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Click here for NO 3 GRAPH

(3a)
TABULATE
S/N:1,2,3,4,5
d(cm):25.00,35.00,50.00,65.00,80.00
I(A):0.80,0.75,0.65,0.60, 0.55
I^-1(A^-1):1.2500,1.3333,1.4286,1.5385,1.6667

(3aviii)
Slope=Change in logI^-1/Change in d(cm)
(Y2-Y1)/(X2-X1)=(0.23-0.06)/(80.0-13.0)
=0.17/67=0.0025
S=0.0025

(3aix)
-I ensure tight connections
-I avoided zero error of the ammeter

(3bii)
-Length of the wire
-temperature
-cross sectional area
-Nature of the material











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100% Waec 2018 Real (Physics Practical) Answers Available Here..

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I didn't see the physics practical answer
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