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100% WAEC 2017 Further Mathematics Answers Available Here
Author: Adera02
Posted on: 00:01:50 Fri, 24 Mar 2017


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100% WAEC 2017 Further Mathematics Answers Available Here


FURTHERMATHS OBJ:
1-10: CBADCBADBB
11-20: DCBDCCDBCC
21-30: ACDCAABBCB
31-40: CDCDDBCAAD
=========================


(1a)
g(x)=y
y=x+6
x=y-6
g^- f(x-6)
=4-5(x-6)/2=4-5x+30/2
=34-5x/2

(1b)
coodinate=(x1+x2/2 ,y1+y2/2)
=(7-2/2,7-5/2)
=(5/2,2/2)
=(5/2,1)

================================


(11a)
Given:
f(x)={(4x-x^2)dx
f(x)=2x^2 - x^3/3 + K
f(3)=2(3)^2 - (3)^2/3 + K =21
18 - 9 + K=11
9+K=21
K=21-9
K=12
Therefore
f(x)= -x^3 + 2x^2 + 12

===========================

(14ai)
SKETCH THE DIAGRAM

(14aii)
Using lami's theory
T1/sin60=T2/sin30
48N/sin60=T2/sin30
48N/0.8660=T2/0.5
0.5(48)/0.8660=T2(0.8660)/0.8660
T2=24/0.8660
T2=27.7N

(14b)
Using the equation of motion
H=U^2/2g
H=(20)^2/2*10
=20*20/20
H=20m
Timetaken to reach the maximum height
S=Ut+1/2at^2
20=0+1/2(100)t^2
20/5=5t^2/5
t^2=4
t=sqroot4
t=2S











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